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Q.

In the reaction ${CH}_{2} = {CH}_{2} + {Br}_{2} \to_{H_{2} O}^{NaCl}$ Product(s) is/are

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a

${CH}_{2} OH - {CH}_{2} OH$

b

${CH}_{2} Br - {CH}_{2} OH$

c

${CH}_{2} Br - {CH}_{2} Cl$

d

${CH}_{2} Br - {CH}_{2} Br$

answer is A, B, C.

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Detailed Solution

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${CH}_{2} Br - {CH}_{2} Br$ , ${CH}_{2} Br - {CH}_{2} OH$ , ${CH}_{2} Br - {CH}_{2} Cl$ are formed.

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