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Q.

In the reaction, ${CH}_{3} COOAg + {Br}_{2} \overset{{CCl}_{4}}{\to} B$ , the compound B is

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a

${({CH}_{3})}_{2} CHBr$

b

$C_{2} H_{5} Br$

c

${CH}_{3} COBr$

d

${CH}_{3} Br$

answer is D.

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Detailed Solution

${CH}_{3} COOAg + {Br}_{2} \overset{{CCl}_{4}}{\to} {CH}_{3} Br + {CO}_{2} + AgBr$ This reaction is Hunsdicker reaction.

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