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In the reaction given below,
$B \leftarrow_{}^{H_{2} - P d / B a S O_{4}} C H_{3} - C \equiv C - C H_{3} \to_{A l c o h o l}^{N a / N H_{3}} A$ A and B are

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A is trans-2-Butene and B is cis -2- Butene

A is cis-2-Butene and B is trans-2-Butene

Trans-2-butene in both cases

Cis-2-butene in both cases

answer is D.

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Detailed Solution

Addition of hydrogen in the presence of Lindlar catalyst give cis, due to the fact that the intermediate is transition state and attack of both hydrogen atom from same side. In Birch reduction the Option-II the intermediate is dianion.

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