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Q.

In the reaction, I2 + 2KClO3  → 2KIO3 + Cl2
i) Iodine is oxidised
ii) Chlorine atom of KClO3 is reduced
iii) Iodine displaces chlorine from KClO3
iv) KClO3 is the reductant
The correct combination is

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a

only iii and iv are correct

b

only i and iv are correct

c

all are correct

d

i, ii and iii are correct

answer is C.

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Detailed Solution

\mathop {{I_2}}\limits^0 + {\text{ }}2\mathop {KCl}\limits^{ + 5} {O_3}\; \to \;\;2K\mathop I\limits^{ + 5} {O_3} + {\text{ }}{\mathop {Cl_2}\limits^0 }
I2 ....reducing agent
\therefore Undergoes Oxidation
KClO3 Oxidizing agent
\therefore Undergoes Reduction
Iodine displaces chlorine

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