In the reaction of oxalate with permanganate in acidic medium, the number of electrons involved in producing one molecule of CO₂ is

The balanced reaction of oxalate with permanganate in an acidic medium is

$2{\mathrm{KMnO}}_4+5{\mathrm{H}}_2{\mathrm{C}}_2{\mathrm{O}}_4+3{\mathrm{H}}_2{\mathrm{SO}}_4\to {\mathrm{K}}_2{\mathrm{SO}}_4+2{\mathrm{MnSO}}_4+10{\mathrm{CO}}_2+8{\mathrm{H}}_2\mathrm{O}$
The number of electrons involved in producing one molecule of CO₂ is

=$\frac{\mathrm{No}. \mathrm{of} \mathrm{electron} \mathrm{involved} \mathrm{in} \mathrm{balanced} \mathrm{reaction}}{\mathrm{No}. \mathrm{of} \mathrm{moles} \mathrm{of} {\mathrm{CO}}_2 \mathrm{produce}} =\frac{10}{10}=1$