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In the reaction of sodium thiosulphate with I₂ in aqueous medium the equivalent weight of sodium thiosulphate is equal to

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The average of molar masses of Na₂S₂O₃ and I₂

Molar mass of sodium thiosulphate x 2

Molar mass of sodium thiosulphate

Half the molar mass of sodium thiosulphate

answer is A.

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Detailed Solution

$2 {Na}_{2} S_{2} O_{3} \cdot 5 H_{2} O + I_{2} ⟶ 2 NaI + {Na}_{2} S_{4} O_{6} or 2 S_{2} O_{3}^{2 -} ⟶ S_{4} O_{6}^{2 -} + 2 e^{-}$
Equivalent weight of ${Na}_{2} S_{2} O_{3} . 5 H_{2} O$
$= \frac{Mol . wt .}{1} = \frac{248}{1} = 248 .$

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