In the reaction sequence, $Ca C_{2} \overset{H_{2} O}{\to} A \to_{{Hg}^{+ 2}}^{dil . H_{2} {SO}_{4}} B \to_{Ni}^{H_{2}} C,$ the product C is

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${CH}_{3} OH$

${CH}_{3} CHO$

$C_{2} H_{4}$

$C_{2} H_{5} OH$

answer is C.

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Detailed Solution

The given reaction sequence is:

CaC₂ → H₂O (A): Calcium carbide (CaC₂) reacts with water to produce acetylene (C₂H₂) and calcium hydroxide (Ca(OH)₂).
C₂H₂ + Hg²⁺ (B): Acetylene (C₂H₂) reacts with mercuric ions (Hg²⁺), leading to the formation of vinyl mercury (C₂H₃Hg).
C₂H₃Hg + Dil. H₂SO₄ (C): The vinyl mercury (C₂H₃Hg) is treated with dilute sulfuric acid (H₂SO₄), which leads to the elimination of mercury and the formation of ethylene (C₂H₄).

So, the product C is C₂H₄ (ethylene).

d. C₂H₄