In the reaction sequence, CaC2→H2OA→Hg+2dil.H2SO4B→NiH2C, the product C is

Book Online Demo

Check Your IQ

Try Test

Courses

Offline Centres

In the reaction sequence, $Ca C_{2} \overset{H_{2} O}{\to} A \to_{{Hg}^{+ 2}}^{dil . H_{2} {SO}_{4}} B \to_{Ni}^{H_{2}} C,$ the product C is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

${CH}_{3} OH$

${CH}_{3} CHO$

$C_{2} H_{4}$

$C_{2} H_{5} OH$

answer is C.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

The given reaction sequence is:

CaC₂ → H₂O (A): Calcium carbide (CaC₂) reacts with water to produce acetylene (C₂H₂) and calcium hydroxide (Ca(OH)₂).
C₂H₂ + Hg²⁺ (B): Acetylene (C₂H₂) reacts with mercuric ions (Hg²⁺), leading to the formation of vinyl mercury (C₂H₃Hg).
C₂H₃Hg + Dil. H₂SO₄ (C): The vinyl mercury (C₂H₃Hg) is treated with dilute sulfuric acid (H₂SO₄), which leads to the elimination of mercury and the formation of ethylene (C₂H₄).

So, the product C is C₂H₄ (ethylene).

d. C₂H₄