In the reaction, 2HgO→2Hg+O2 , Hg2+ act as

In the reaction, 2HgO→2Hg+O2, the oxidation states of Hg and O.The oxidation state of Hg changes from +2 to 0 i.e. Hg gets reduced. Whereas, the oxidation state of O changes from -2 to 0 . Oxygen gets oxidized. So, Hg2+ gets reduced and oxidized O. Hence, it acts as an oxidizing agent (a substance that causes oxidation by accepting electrons and itself gets reduced).

In the reaction, 2HgO→2Hg+O2 , Hg2+ act as

In the reaction, 2HgO→2Hg+O2, the oxidation states of Hg and O.The oxidation state of Hg changes from +2 to 0 i.e. Hg gets reduced. Whereas, the oxidation state of O changes from -2 to 0 . Oxygen gets oxidized. So, Hg2+ gets reduced and oxidized O. Hence, it acts as an oxidizing agent (a substance that causes oxidation by accepting electrons and itself gets reduced).

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In the reaction, $2 HgO \to 2 Hg + O_{2}, {Hg}^{2 +}$ act as

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Reducing agent

Oxidized

None of the above

Oxidizing agent

answer is A.

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Detailed Solution

In the reaction, $2 HgO \to 2 Hg + O_{2}$ , the oxidation states of Hg and O.
The oxidation state of $Hg$ changes from $+ 2$ to 0 i.e. $Hg$ gets reduced. Whereas, the oxidation state of $O$ changes from $- 2$ to 0 . Oxygen gets oxidized. So, ${Hg}^{2 +}$ gets reduced and oxidized $O$ . Hence, it acts as an oxidizing agent (a substance that causes oxidation by accepting electrons and itself gets reduced).