In the reaction $4\mathrm{A}+2\mathrm{B}+3\mathrm{C}⟶{\mathrm{A}}_4{\mathrm{B}}_2{\mathrm{C}}_3\mathrm{w}$ what will be the number of moles of product formed? Starting from 2 moles of A, 1.2 moles of B and 1.44 moles of C.

                    $4\mathrm{A}+2\mathrm{B}+3\mathrm{C}⟶{\mathrm{A}}_4{\mathrm{B}}_2{\mathrm{C}}_3\mathrm{w}$

                       $2\text{ mole }1.21.44$

  Simple Ratio   $\frac{2}{4}\frac{1.2}{2}\frac{1.44}{3}$

                                         (L.R.) O.48