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In the reaction,
$4 {NH}_{3} (g) + 5 O_{2} (g) \to 4 NO (g) + 6 H_{2} O (l)$
When 1 mole of ammonia and 1.25 moles of $O_{2}$ are made to react to completion. Correct statement is

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All the oxygen will be consumed

2.0 mole of NO will be produced

1.0 mole of $H_{2} O$ is produced

0.5 moles of ammonia will be consumed

answer is A.

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Detailed Solution

1 mole $N H_{3}$ completely reacts with 1.25
moles of $O_{2}$ to give 1 mole of NO and 1.5
moles of $H_{2} O$ . No reactant inexcess

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