In the reaction

$\mathrm{A}+{\mathrm{B}}_2⟶{\mathrm{AB}}_2$

Find out in which option(s) ${\mathrm{B}}_2$ is limiting reagent. 

[Molar mass :$M_A=10\mathrm{g}{\mathrm{mole}}^{-1},M_B=20\mathrm{g}{\mathrm{mol}}^{-1}$

The moles in the reaction for all the option, 

$$\begin{gathered} \mathit{ }\mathit{ }A\mathit{ }\mathit{ }+ B_{2 }\to A{B}_2 \\ \mathit{\left(}a\mathit{\right)}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{30}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{10}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ } \\ \mathit{\left(}b\mathit{\right)}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{2}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\frac{\mathit{3}}{\mathit{2}} \\ \mathit{\left(}c\mathit{\right)}\mathit{ }\mathit{ }\mathit{ }\mathit{100}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{50} \\ \mathit{\left(}d\mathit{\right)}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{5}\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{ }\mathit{12}\mathit{.}\mathit{5} \end{gathered}$$