In the reaction ${\mathrm{C}}_2{\mathrm{H}}_4\stackrel{\mathrm{x}}{⟶}$ Product, if the hybridization of carbon atom (s) in the product is ${\mathrm{sp}}^3,\mathrm{X}$ is not

In the given reaction C₂H₄ ⟶ X Product, the determination of hybridization depends on the type of reaction and the product formed. The key factor to consider is the reagents used. When ozone (O₃) followed by zinc and water (Zn + H₂O) is employed, the process known as ozonolysis occurs. In this reaction, the alkene, C₂H₄, is broken into smaller compounds, specifically aldehydes or ketones. Both of these products have carbon atoms that remain sp² hybridized.

In contrast, other reactions typically lead to products in which the carbon atoms become sp³ hybridized. For example, hydrogenation of C₂H₄ or reactions involving halogens can convert the initial double-bonded carbons into single-bonded (sigma bond) carbons, resulting in sp³ hybridization.

Thus, to answer the question, when the product has sp³ hybridization, X could be any reagent except O₃/Zn + H₂O, as ozonolysis does not yield sp³ hybridized carbons. Instead, it produces aldehydes or ketones with sp² hybridized carbon atoms. This reaction highlights a specific instance where the original alkene’s hybridization shifts from sp² to sp³ (except in the case of ozonolysis).

In summary, the reagents O₃/Zn + H₂O do not lead to sp³ hybridization in the product, making X a unique case. This distinction is crucial for understanding C₂H₄ hybridization and how it changes under different chemical conditions.