In the reaction CH3−CH=CH−CHO→oxidizing agentCH3−CH=CH−COOHThe oxidizing agent can be

CH3CH−CH−CHO→ benedictsolution CH3−CH=CH−COOHBenedict solution (solution of CuSO4 ,sodium carbonate and sodium citrate) is specific for oxidation of Aldehydes.

In the reaction CH3−CH=CH−CHO→oxidizing agentCH3−CH=CH−COOHThe oxidizing agent can be

CH3CH−CH−CHO→ benedictsolution CH3−CH=CH−COOHBenedict solution (solution of CuSO4 ,sodium carbonate and sodium citrate) is specific for oxidation of Aldehydes.

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In the reaction ${CH}_{3} - CH = CH - CHO \overset{oxidizing agent}{\to} {CH}_{3} - CH = CH - COOH$
The oxidizing agent can be

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Alkaline ${KMnO}_{4}$

Acidified $K_{2} {Cr}_{2} O_{7}$

Benedict’s solution

All the above

answer is C.

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Detailed Solution

${CH}_{3} CH - CH - CHO \overset{benedictsolution}{\to} {CH}_{3} - CH = CH - COOH$
Benedict solution (solution of CuSO₄ ,sodium carbonate and sodium citrate) is specific for oxidation of Aldehydes.