In the reaction ${Cr}_2{O}_7^{2-}+14H^{+}+6I^{-}\to 2{Cr}^{3+}+3H_{2}O+I_2$. which element is reduced?

The given chemical reaction is as follows:

${Cr}_2{O}_7^{2-}+14H^{+}+6I^{-}\to 2{Cr}^{3+}+3H_{2}O+I_2$.

The oxidation state of chromium in ${Cr}_2{O}_7^{2-}$ changes from +6 to +3 hence it is getting reduced.

Hence the correct option is (B).