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Q.

In the reaction $C (s) + {CO}_{2} (g) ⇌ 2 CO (g)$ , the equilibrium pressure is 12 atm. If 50% of ${CO}_{2}$ reacts then Kp will be

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a

16 atm

b

24 atm

c

12 atm

d

20 atm

answer is B.

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Detailed Solution

Now, the reaction we have,

$\begin{array}{lcr} C (s) + {CO}_{2} (g) ⇌ 2 CO \\ t = 0 & P & - \\ At (e q), & \frac{P}{2} & P \end{array}$

$\begin{array}{l} \Rightarrow \frac{3 P}{2} = 12 \\ or P = 8 \\ K_{P} = \frac{8^{2}}{4} \\ = 16 \end{array}$

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