In the reaction(i) H2O2+O3⟶2H2O+2O2(ii) PbS+4O3→PbSO4+4O2

O 3 is oxidized in (i) and reduced in (ii)

O 3 is oxidized in (i) and reduced in (ii)

O 3 is reduced both in (i) and (ii)

O 3 is oxidized both in (i) and (ii)

O 3 is oxidized in (i) and reduced in (ii)

O 3 is reduced in (i) and oxidized in (ii)

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In the reaction
(i) $H_{2} O_{2} + O_{3} ⟶ 2 H_{2} O + 2 O_{2}$
(ii) $PbS + 4 O_{3} \to {PbSO}_{4} + 4 O_{2}$

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O₃ is reduced both in (i) and (ii)

O₃ is oxidized both in (i) and (ii)

O₃ is oxidized in (i) and reduced in (ii)

O₃is reduced in (i) and oxidized in (ii)

answer is C.

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Eq. (i) may be represented as

$H_{2} O_{2} \to H_{2} O + O$ and $O_{3} + O \to 2 O_{2}$

Eq. (ii) may be represented as

$O_{3} \to O_{2} + O$ and $PbS + 4 O \to {PbSO}_{4}$

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