In the reaction, PCl5⇌PCl3+Cl2, the amounts of PCl5, PCl3 and Cl2 at equilibrium are 2 mole each and the total pressure is 3 atm. The equilibrium constant Kp is

Kp− nCl2×nPCl3 nPCl5×pΣn1=2×22×361=1atm

In the reaction, PCl5⇌PCl3+Cl2, the amounts of PCl5, PCl3 and Cl2 at equilibrium are 2 mole each and the total pressure is 3 atm. The equilibrium constant Kp is

Kp− nCl2×nPCl3 nPCl5×pΣn1=2×22×361=1atm

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In the reaction, ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ , the amounts of PCl₅, PCl₃ and Cl₂ at equilibrium are 2 mole each and the total pressure is 3 atm. The equilibrium constant K_p is

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6.0 atm

2.0 atm

1.0 atm

3.0 atm

answer is A.

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$K_{p} - \frac{^{n} {Cl}_{2} \times^{n} {PCl}_{3}}{^{n} {PCl}_{5}} \times {[\frac{p}{Σn}]}^{1} = 2 \times \frac{2}{2} \times {[\frac{3}{6}]}^{1} = 1 atm$

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In the reaction, PCl5⇌PCl3+Cl2, the amounts of PCl5, PCl3 and Cl2 at equilibrium are 2 mole each and the total pressure is 3 atm. The equilibrium constant Kp is

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In the reaction, ${PCl}_{5} ⇌ {PCl}_{3} + {Cl}_{2}$ , the amounts of PCl₅, PCl₃ and Cl₂ at equilibrium are 2 mole each and the total pressure is 3 atm. The equilibrium constant K_p is