In the reactions given below, the product  formed is alcohol in the case of

$\mathrm{A}.{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5\stackrel{\mathrm{DiBAL}-\mathrm{H}}{\to }$

$\mathrm{B}.{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5\stackrel{{\mathrm{LiAlH}}_4}{\to }$

$\mathrm{C}.{\mathrm{CH}}_3{\mathrm{COOC}}_2{\mathrm{H}}_5\underset{{\mathrm{H}}^{+}}{\overset{{\mathrm{H}}_2\mathrm{O}}{\to }}$