In the reduction of nitrobenzene, which of the following is the intermediate

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$C_{6} H_{5} N = O$

$C_{6} H_{5} N = \overset{\overset{O}{↑}}{N} - C_{6} H_{5}$

$C_{6} H_{5} - N = N - C_{6} H_{5}$

$C_{6} H_{5} NH - NH - C_{6} H_{5}$

answer is A.

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Detailed Solution

In acidic medium if nitro benzene is reduced along with tin and concentrated HCl acid, then it is reduced or converted to aniline. When reduced in alkaline medium, nitro benzene forms some intermediate products like Nitrosobenzene and Phenyl hydroxylamine which undergo bi-molecular condensation reaction

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