AI Mentor

Check Your IQ

Free Expert Demo

Try Test

Courses

Dropper NEET Course Dropper JEE Course Class - 12 NEET Course Class - 12 JEE Course Class - 11 NEET Course Class - 11 JEE Course Class - 10 Foundation NEET Course Class - 10 Foundation JEE Course Class - 10 CBSE Course Class - 9 Foundation NEET Course Class - 9 Foundation JEE Course Class -9 CBSE Course Class - 8 CBSE Course Class - 7 CBSE Course Class - 6 CBSE Course

Offline Centres

In the relation $F = G \frac{Mm}{d²}$ , the quantity G:

see full answer

Your Exam Success, Personally Taken Care Of

1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.

An Intiative by Sri Chaitanya

Depends upon the value of g at the place of observation.

Is used only when the earth is one of the two masses.

Is greatest at the surface of the earth.

It is a universal constant of nature.

answer is D.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

The G is the universal constant of nature.
It is the constant of proportionality in Newton’s universal law of gravitation. The accepted value of G is

6.67 \times 10^{- 11} N m^{2} {kg}^{- 2}

. Gravitational constant G is equal to “ the force of attraction acting between two bodies each of unit mass, whose centres are placed a unit distance apart.”
Question Image

●       It has the same value at all places
●       It can never be zero
●       It is a scalar quantity

Watch 3-min video & get full concept clarity

courses

No courses found

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Online Course for IIT JEE

Best Online Course for NEET

Best Online Course for CBSE

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Get Expert Academic Guidance – Connect with a Counselor Today!