In the Rutherford scattering experiment, the number of alpha particles scattered at an angle $θ = 60^{0}$ is 36 per minute. The number of alpha particles per minute scattered at angles $θ = 90^{0}$ is (Assume all other conditions to be identical)

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answer is 9.

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Detailed Solution

$N_{α} α \frac{1}{\sin^{4} (\frac{θ}{2})} ∴ \frac{N_{1}}{N_{2}} = {[\frac{\sin (\frac{90}{2})}{\sin (\frac{60}{2})}]}^{4} \Rightarrow \frac{36}{N_{2}} = \frac{4}{1} \Rightarrow N_{2} = 9$

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