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Q.

In the sequence {1}, {2, 3}, {4, 5, 6}, {7, 8, 9, 10}........ of sets, the sum of elements in the nth set is

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a

n(n+1)6

b

n(n2+1)2

c

n(n+1)(n+2)6

d

n(n+1)3

answer is B.

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Detailed Solution

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1, 2, 3, 4, 5, 6, 7, 8, 9, 10

Sn last term ==n(n+1)2

first term a=(n-1)+1

                    =n(n-1)2+1

d=1,  no. of terms = n

Sn=n2 a+1 =n2 n(n-1)2+1+n(n+1)2 =n2 2n22+1=nn2+12

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