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In the series sequence of two engines E₁ and E₂ then T₁ = 600K and T₂ = 300K. it is given that both the engines working on Carnot principle have same efficiency, then temperature T at which exhaust of E₁ is fed into E₂ is equal to $300 \sqrt{n} K$ . Value of n is equal to

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answer is 2.

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Detailed Solution

$η_{1} = 1 - \frac{T_{1}}{600}$
$η_{2} = 1 - \frac{300}{T}$
Given: $\Rightarrow \frac{T}{600} = \frac{300}{T} \Rightarrow T = \sqrt{180000} K = 300 \sqrt{2} K$ $\Rightarrow n = 2$

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