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In the shown arrangement of three identical blocks each of mass m = 1 kg and an ideal spring $(k = 300 N / m)$ , if the system is set free when spring was in its natural lengths.

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Maximum speed of each block = $\frac{1}{3} m / s$

At $x = \frac{2 m g}{K}$ speed is maximum

Maximum speed of each block = $\frac{2}{3} m / s$

Maximum speed will be at equilibrium position

answer is A, B, D.

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Detailed Solution

$V = V_{M a x}$ at $x = \frac{2 m g}{k}$

$Δ P E = Δ K E$

$(2 m g) x = \frac{1}{2} K x^{2} + \frac{1}{2} (3 m) ({V_{i}}^{2}) \Rightarrow V = 2 g \sqrt{\frac{m}{3 K}} = \frac{2}{3} m / s$

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