Courses
Q.
In the shown experimental setup to study photoelectric effect, two conducting electrodes are enclosed in an evacuated glass-tube as shown. A parallel beam of monochromatic radiation falls on photosensitive electrode. Assume that for each photons incident, a photoelectron is ejected if its energy is greater than work function of electrode. Match the statements in list-I with corresponding graphs in list-II
List-I | List-II | ||
P | Photocurrent versus intensity of radiation is represented by | 1 | |
Q | Maximum kinetic energy of ejected photoelectrons versus frequency for electrodes of different work function is represented by | 2 | |
R | Photo current versus applied voltage for different intensity of radiation is represented by | 3 | |
S | Photo current versus applied voltage at constant intensity of radiation for electrodes of different work function. | 4 | |
5 | none |
see full answer
Start JEE / NEET / Foundation preparation at rupees 99/day !!
a
P-1; Q-3; R-2; S-4
b
P-3; Q-4; R-1; S-2
c
P-3; Q-2; R-5; S-4
d
P-2; Q-1; R-4; S-3
answer is C.
(Unlock A.I Detailed Solution for FREE)
Ready to Test Your Skills?
Check your Performance Today with our Free Mock Test used by Toppers!
Take Free Test
Detailed Solution
(A) In the given spontaneous radioactive decay, the number of protons remains constant and all conservation principles are obeyed.
(B) In fusion reaction of two hydrogen nuclei a proton is decreased as positron shall be emitted in the reaction. All the three conservation principles are obeyed.
(C) In the given fission reaction the number of protons remains constant and all conservation principles are obeyed.
(D) In beta negative decay, a neutron transforms into a proton within the nucleus and the electron is ejected out.