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Q.

In the situation given, a force of 100 N is acting on a block placed on rough horizontal surface

            as shown in the figure. The block does not slide. If the angle of friction is found to betan11n.

            Find the value of n. Take g=10 m/s2____

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answer is 2.

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Detailed Solution

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N=Fsin37°+mg=10035+100 =160N μ=FN=FxN=100cos37°160 =80160=12 μ=Tanϕ=1n 1n=12n=2

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