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In the solid state, $P C l_{5}$ exists as an ionic solid, which contains a cation and anion, The hybridization of ‘P’ atom in the anionic and cationic parts respectively, are

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$s p^{3}$ and $s p^{3} d$

$s p^{3}$ and $s p^{3}$

$s p^{3} d^{2}$ and $s p^{3}$

$s p^{3}$ and $s p^{3} d^{2}$

answer is C.

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Detailed Solution

${[P C l_{4}]}^{+} {[P C l_{6}]}^{-}$
Anionic part = ${[P C l_{6}]}^{-} = s p^{3} d^{2}$
Cationic part = ${[P C l_{4}]}^{+} = s p^{3}$

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