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Q.

In the standard Young’s double slit experimental set-up the intensities of both the slits are equal and the fringe width is found to be β . The minimum distance between two points on the screen where the intensity is one fourth of intensity at a maxima is

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a

β

b

β / 2

c

β / 4

d

β / 3

answer is C.

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Detailed Solution

Ive=Imaxcos2δ2=Imax4cosδ2=12δ=2π3Δx=λ3x=ΔxDd=λD3d

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