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In the steady state the two ends of a meter rod are at 30°C and 20°C , the temperature at the 40th cm from the end at higher temperature is

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22°C

26°C

25°C

24°C

answer is B.

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Detailed Solution

$Q = \frac{KA (Δθ) t}{l} \Rightarrow \frac{θ_{1} - θ_{2}}{L} = \frac{θ - θ_{1}}{l}$

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