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Q.

In the Sulphur estimation 0.471 g of an organic compound gave 1.44g of barium sulphate. The percentage of Sulphur in the compound is ____ % ( nearest Integer)

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a

42

b

41

c

39

d

40

answer is D.

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Detailed Solution

Given data:

        Mass of an organic compound = 0.471 g

        Mass of Barium sulphate= 1.44 g

      To find = Percentage of Sulphur.

Explanation:

We know, Molecular mass of BaSO4 = 233 g mol-1
Therefore, Sulphur content in 233 g mol-1 BaSO4 = 32 g mol-1
Thus, Sulphur content in 1 g mol-1 BaSO432233g mol-1
Thus, Sulphur content in 1.44 g mol-1 BaSO4 = 32233×1.44 g mol-1
Therefore in 0.471 g of organic compound, percentage of Sulphur  =  32233×1.44×10.471×100 % = 41.971 % = 42% (approx)

Hence, the correct option is option (D) 42.

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