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In the system shown below, friction and mass of the pulley are negligible. Find the acceleration of $M_{2}$ if $M_{1} = 125 g, M_{2} = 500 g$ and F = 15 N. Mark your answers in SI units

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answer is 15.

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Detailed Solution

Using constraints relation, if acceleration of block of mass $M_{2}$ is a, acceleration of $M_{1}$ is 2a. Now using Newton’s laws for the two blocks:
$T = M_{1} (2 a) a n d F - 2 T = M_{2} (a)$
Which gives: $a = \frac{F}{M_{2} + 4 M_{1}}$

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