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Q.

In the system shown in figure m1 > m2. System is held at rest by thread BC.Just after the thread BC is burnt.
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a

acceleration of m1 will be equal to zero

b

acceleration of m2 will be downwards

c

magnitude of accceleration of both of blocks will be m1m2m1+m2g

d

magnitudes of acceleration of two blocks will be non- zero and unequal

answer is A.

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Detailed Solution

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Initiallym1gky=T1
T1=m2g+T2
Immediately after burning BC
aB=T1m2gm2=m1m2m2g  upward aA=0

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