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In the two vessels of same volume , atomic hydrogen and helium at pressure 1 atm and 2 atm are filled . If temperature of both the sample is same then average speed of hydrogen atoms $< C_{H} >$ will be related to that of helium $< C_{H e} >$

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$< C_{H} > = \frac{< C_{H e} >}{2}$

$< C_{H} > = \sqrt{2} < C_{H e} >$

$< C_{H} > = 2 < C_{H e} >$

$< C_{H} > = < C_{H e} >$

answer is C.

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Detailed Solution

$v_{avg} = \sqrt{\frac{8 RT}{π M}}$

$< C_{H} > = \sqrt{\frac{8 RT}{π 1}}$

$< C_{He} > = \sqrt{\frac{8 RT}{4 π}} = \frac{1}{2} < C_{H} >$

So, $< C_{H} > = 2 < C_{He} >$

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