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In the word “ENGINEERING” if all E’s are not together and N’s come together then number of permutations is

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$\frac{9!}{3! 2!} - \frac{7!}{2! 2!}$

$\frac{9!}{3! 2! 2!} - \frac{7!}{2! 2!}$

$\frac{9!}{2! 2!} - \frac{7!}{2! 2!}$

$\frac{9!}{3! 2! 2!} - \frac{7!}{2! 2! 2!}$

answer is D.

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Detailed Solution

Total = permutations when 3E’s are not together – (when 3E’s and 3N’s are together) $= \frac{9!}{3! 2! 2!} - \frac{7!}{2! 2!}$

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