Q.

In this 100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in English alphabets in the surnames was obtained as follows:

Number of letters1-44-77-1010-1313-1616-19
Number of surnames630401644

Determine the number of median letters in the surnames. Find the number of mean letters in the surnames and also, find the size of modal in the surnames.

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answer is 1.

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Detailed Solution

To calculate median:

Class IntervalFrequencyCumulative Frequency
1-466
4-73036
7-104076
10-131692
13-16496
16-194100

Given:

n = 100 &n2 = 50

Median class = 7-10

Therefore, l = 7, Cf = 36, f = 40 & h = 3

Ncert solutions class 10 chapter 14-6

Median = 7+(50-3640) × 3

Median = 7+4240

Median=8.05

Calculate the Mode:

Modal class = 7-10,

Where, l = 7, f1 = 40, f0 = 30, f2 = 16 & h = 3

Ncert solutions class 10 chapter 14-7

Mode = 7+(40-3080-30-16) × 3

= 7+3034

= 7.88

Therefore mode = 7.88

Calculate the Mean:

Class Intervalfixifixi
1-462.515
4-7305.5165
7-10408.5340
10-131611.5184
13-16414.551
16-19417.570
 Sum fi = 100 Sum fixi = 825

Mean = x̄ =  fixi fi 

Mean = 825100 = 8.25

Therefore, mean = 8.25

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