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Q.

In this figure how much force on mass m = 5kg should be applied, so that it just won't slip. Given that car is moving with constant acceleration $a = 5 {m/s}^{2}$ :

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a

150 N

b

170 N

c

250 N

d

180 N

answer is D.

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Detailed Solution

$mg = f$

$50 = 0 .4 (N - ma)$

$\frac{50}{0.4} = N - ma$

$125 = N - 5 \times 5$

$N = 150N$

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