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Q.

In this figure the resistance of the coil of galvanometer G is 2 Ω. The emf of the cell is 4 V. The ratio of potential difference across C1 and C2 is

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a

1

b

34

c

54

d

45

answer is D.

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Detailed Solution

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i=46+2+8=14AVA=4V,VD=0VVB=VA−i(6)=4−14×6=2.5VVC=VB−i(2)=2.5−14×2=2V Across C1,V1=VA−VC=4−2=2V Across C2,V2=VB−VD=2.5−0=2.5V∴V1V2=22.5=45

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