In this question, each option has two statements, S-I and S-II. S-II is a statement related to S-I. Choose the option in which S-II is INCORRECT explanation of S-I.

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S-I : Ethyl amine is soluble in water whereas aniline is not.
S-II: The hydrophobic part of aniline is larger than that of ethyl amine.

S-I : Methyl amine in water reacts with ferric chloride to precipitate hydrated ferric oxide.
S-II: Methylamine acts as a Bronsted base in water.

S-I :Although amino group is o- and p- directing in aromatic electrophilic substitution reactions, aniline on nitration gives a substantial amount of m-nitroaniline.
S-II: Aniline undergoes protonation in acidic medium to become anilinium ion.

S-I : $M e_{3} N$ is more basic than $M e_{2} N H$ in vapour phase while reverse is true in aqueous solution.
S-II: Inductive effect dominates over hydrogen bonding in aqueous solution.

answer is D.

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