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Q.

In trapezium ABCD, AB||DC and DC=2AB.EF   is drawn parallel to AB cuts AD in F and BC in E such that BE:EC=3:4   . Diagonal D B intersects EF at G. State if the given statement is condition true or false, “ 7EF=10AB  ”.


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a

False

b

True 

answer is A.

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Detailed Solution

It is given that:
ABCD is a trapezium. where AB||DC
 And, DC = 2 AB .......(1)
 and BE: EC = 3:4.............(2)
From equation we can write that:
  BE EC = 3 4 BE EC +1= 3 4 +1 BE+EC EC = 7 4 BC EC = 3 4   Since, the ΔCGE and triangles ΔCAB are similar triangles the ratio of corresponding sides is equal.
  EG AB = EC BC = 4 7  
7EG=4AB   Therefore,  AF FD = EB EC = 3 4  
  FD AF = 4 3   FD AF +1= 4 3 +1  
FD+AF AF = 7 3   AD AF = 7 3  
Since, the triangles AFG and ADC are similar triangles.
FG CD = AF AD = 3 7 7FG=3CD From equation (1) 7FG=6AB.(4) Adding (3) and (4) 7(EG+FG)=10AB 7EF=10AB  
From the given conditions, it is derived that 7EF=10AB.
The given statement is true.
Hence, the correct option is 2.
 
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