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In triangle $ABC, b, c$ values are given and the error in $A$ is $δA,$ then $δa =$

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$bc \sin A . δA$

$\frac{2 ∆ δA}{a}$

$\frac{∆}{2 a}' δA$

answer is A.

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Detailed Solution

$a^{2} = b^{2} + c^{2} - 2 bc \cos A 2 a δa = - 2 bc (- \sin A) δA δa = \frac{bc}{a} \sin A δA ∆ = \frac{1}{2} bc \sin A δa = \frac{2 ∆}{a} \sqrt{A}$

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