In Vernier callipers instrument 20 vernier scale divisions coincide with 18 main scale divisions where 1 mm = 1 main scale division. The least count of callipers (in mm) is $\frac{1}{x}$ . Then x is ___

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answer is 10.

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Detailed Solution

L.C. = M.S.D-V.S.D
20(VSD) =18(MSD)
$\begin{array}{l} \Rightarrow VSD = \frac{18}{20} MSD \\ ∴ L.C. = (1 - \frac{18}{20}) MSD = \frac{2}{20} \times 1 mm \\ = 0 .1 mm \end{array}$

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