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In vibration magnetometer experiment, a bar magnet is heated so as to reduce its magnetic moment by 36%. By doing this the periodic time of the oscillation will

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Increases by 36%

Increases by 25%

Decreases by 25%

Decreases by 64%

answer is B.

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Detailed Solution

$T = 2 π \sqrt{\frac{I}{M B_{H}}}$ $\Rightarrow T \propto \frac{1}{\sqrt{M}}$

$\Rightarrow \frac{T_{1}}{T_{2}} = \sqrt{\frac{M_{2}}{M_{1}}}$

If $M_{1} = 100$ then $M_{2} = (100 - 36) = 64$
So $\frac{T_{1}}{T_{2}} = \sqrt{\frac{64}{100}} = \frac{8}{10}$ $\Rightarrow T_{2} = \frac{10}{8} T_{1} = 1.25 T_{1}$
So % increase in time period = 25%

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