In what ratio amounts of H₂SO₄ and H₃PO₄ react with the same amounts of NaOH to form normal salts?

${\mathrm{H}}_2{\mathrm{SO}}_4+2\mathrm{NaOH}⟶{\mathrm{Na}}_2{\mathrm{SO}}_4+2{\mathrm{H}}_2\mathrm{O}$

$$\begin{gathered} \text{ moles of }{\mathrm{H}}_2{\mathrm{SO}}_4\text{ required for }1\mathrm{mol}\text{ of }\mathrm{NaOH}=\frac{1}{2}=0.5 \\ {\mathrm{H}}_3{\mathrm{PO}}_4+3\mathrm{NaOH}⟶{\mathrm{Na}}_3{\mathrm{PO}}_4+3{\mathrm{H}}_2\mathrm{O} \\ \text{ moles of }{\mathrm{H}}_3{\mathrm{PO}}_4\text{ required for }1\mathrm{mol}\text{ of }\mathrm{NaOH}=\frac{1}{3} \\ \text{ Hence, mass of }{\mathrm{H}}_2{\mathrm{SO}}_4:\text{ mass of }{\mathrm{H}}_3{\mathrm{PO}}_4=\frac{1}{2}:\frac{1}{3} \\ =3:2\left({\mathrm{M}}_{{\mathrm{H}}_2{\mathrm{SO}}_4}={\mathrm{M}}_{{\mathrm{H}}_3{\mathrm{PO}}_4}=98\right) \end{gathered}$$