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Q.

In what ratio by mass carbon monoxide and nitrogen should be mixed so that partial pressure exerted by each gas is same?

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a

1 : 1

b

1 : 2

c

2 : 1

d

3 : 4

answer is A.

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Detailed Solution

Molecular weight of carbon monoxide and nitrogen are same has result

$n_{CO} = n_{N_{2}} \frac{w_{CO}}{28} = \frac{w_{N_{2}}}{28} ∴ w_{CO} : w_{N_{2}} = 1 : 1$

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