In what volume of water in liters, 20gm of NaOH as to be dissolved such that 400ml of this solutions exactly neutralize 4.9gm of $H_{2} {SO}_{4}$ is

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answer is 2.

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Detailed Solution

$N = \frac{4 .9}{49} \times \frac{1000}{400} = 0 .25 N$
$Volume of water (v) = \frac{cut}{GEw} \times \frac{1000}{N} = \frac{20}{40} \times \frac{1000}{0 .25} = 2 liters$

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