In which case C-C bond length will be highest?

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$F_{2} CH - {CHF}_{2}$

${FCH}_{2} - {CH}_{2} F$

${CF}_{3} - {CF}_{3}$

${CH}_{3} - {CF}_{3}$

answer is C.

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Detailed Solution

In ${FCH}_{2} - {CH}_{2} F$ case C-C bond length will be highest.

Greater electronegative substituents are bonded to hybrid orbitals with more p-character in accordance with Bent's Rule.

Thus, the bond length will be longer as the p-characters is more.

Electronegative element $↑$ , the p-character to attached orbital $↑$ $% s$ of $C - C$ $↑$ , B.L. $↓ .$

Hence, the option C is correct.

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