In which case does chromium undergo reduction?

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$\begin{aligned} {CrO}_{3} ⟶ {CrOF}_{3} \end{aligned}$

$\begin{array}{r} {Cr}^{3 +} ⟶ Cr (OH)_{4}^{-} \end{array}$

$\begin{array}{r} 2 {CrO}_{4}^{2 -} ⟶ {Cr}_{2} O_{7}^{2 -} \end{array}$

${Cr}^{3 +} ⟶ {CrO}_{4}^{2 -}$

answer is A.

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Detailed Solution

Since the oxidation number in the chromium is decreasing from +6 to +5 it result in the reduction.
$\underset{+ 6}{{CrO}_{3} \to} \underset{(+ 5) - 2 - 3}{{CrOF}_{3}}$
Hence correct option is A.

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