In which case is number of molecules of water maximum?

$\text{ (a) Mass of water }=V\times d=18\times 1=18 \mathrm{g}$

$\text{ Molecules of water }=\mathrm{mole}\times {\mathrm{N}}_{\mathrm{A}}=\frac{18}{18}{\mathrm{N}}_{\mathrm{A}}={\mathrm{N}}_{\mathrm{A}}$

$\text{ (b) Molecules of water }=\text{ mole }\times {\mathrm{N}}_{\mathrm{A}}=\frac{0.18}{18}{\mathrm{N}}_{\mathrm{A}}={10}^{-2}{\mathrm{N}}_{\mathrm{A}}$

$\text{ (c) Moles of water }=\frac{0.00224}{22.4}={10}^{-4}$

$\text{ Molecules of water }=\text{ mole }\times {\mathrm{N}}_{\mathrm{A}}={10}^{-4}{ \mathrm{N}}_{\mathrm{A}}$

$\text{ (d) Molecules of water }=\text{ mole }\times {\mathrm{N}}_{\mathrm{A}}={10}^{-3}{\mathrm{N}}_{\mathrm{A}}$