In which if the following the total surface area and volume are numerically equal ?

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A cube of side 2 cm

A cube of side 6 cm

A cube of side 3 cm

A cube of side 4 cm

answer is D.

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Detailed Solution

T.S.A of Cube with 2cm

= 6 a^{2} = 6 \times 2^{2} = 24 c m^{2}

Volume of Cube with 2cm $= a^{3} = 2^{3} = 8 c m^{3}$

T.S.A of Cube with 3cm $= 6 a^{2} = 6 \times 3^{2} = 54 c m^{2}$

Volume of Cube with 3cm $= a^{3} = 3^{3} = 27 c m^{3}$

T.S.A of Cube with 4cm $= 6 a^{2} = 6 \times 4^{2} = 96 c m^{2}$

Volume of Cube with 4cm $= a^{3} = 4^{3} = 64 c m^{3}$

T.S.A of Cube with 6cm $= 6 a^{2} = 6 \times 6^{2} = 216 c m^{2}$

Volume of Cube with 6cm $= a^{3} = 6^{3} = 216 c m^{3}$

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