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Q.
In which of the fallowing molecule have highest bond angle in 15th group hydrides( EH3)
A=NH3, B= PH3, C=AsH3, D= SbH3 E= BiH3
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a
B
b
C
c
A
d
E
answer is A.
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Detailed Solution
All the elements of Group 15 form hydrides of the type EH3 where E = N, P, As, Sb or Bi. The hydrides show regular gradation in their properties. The stability of hydrides decreases from NH3 to BiH3 which can be observed from their bond dissociation enthalpy. Consequently, the reducing character of the hydrides increases. Ammonia is only a mild reducing agent while BiH3 is the strongest reducing agent amongst all the hydrides. Basicity also decreases in the order NH3 > PH3 > AsH3 > SbH3 > BiH3. Due to high electronegativity and small size of nitrogen, NH3 exhibits hydrogen bonding in solid as well as liquid state. Because of this, it has higher melting and boiling points than that of PH3 .
Central atom size order :NH3 < PH3 < AsH3 < SbH3 < BiH3
Bond length order: NH3 < PH3 < AsH3 < SbH3 < BiH3
Bond energy order :NH3 > PH3 > AsH3 > SbH3 > BiH3
Enthalpy of formation order:NH3 > PH3 > AsH3 > SbH3 > BiH3
Bond angle order : NH3 > PH3 > AsH3 > SbH3 > BiH3
Thermal stability order : NH3 > PH3 > AsH3 > SbH3 > BiH3
Basic nature order :NH3 > PH3 > AsH3 > SbH3 > BiH3
Reducing power order :NH3 < PH3 < AsH3 < SbH3 < BiH3
H- bonding capacity order : NH3 > PH3 > AsH3 > SbH3 > BiH3
Central atom electro negativity order :NH3 > PH3 > AsH3 > SbH3 > BiH3
S-character percentage at central atom order : NH3 > PH3 > AsH3 > SbH3 > BiH3
Melting point order : PH3 < AsH3 < SbH3 < NH3< BiH3
Boiling point order : PH3 < AsH3 <NH3 < SbH3 < BiH3
vapourisation order : PH3 > AsH3 > SbH3 > NH3 >BiH3
Enthalpy of vapourisation : PH3 < AsH3 < SbH3 < NH3< BiH3